Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,
Where, p is the probability of success
q is the probability of failure q=1-p,
n is total number of trials n=8
r=3
Substitute the values,
Therefore, the probability that 8 mice are required is 0.2428.
A^2 + b^2 =c ^2
7.3^2 + 4.8^2 = c^2
C^2= 76.33
C= square root of 76.33
C= 8.7
Which is d
U should use friendly numbers when subtracting.......the numbers have to be between 3 and 10
6,720,000. I hope that helps!
Answer:
the final option: -2x to the power of nine
Step-by-step explanation:
honestly i'm in 20 minutes of sleep so i really hope you don't need the explanation
-the tired korean