I think its D. 32.6 s/ft and appoximatley 0.03 ft/s
Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
Hey ! I know for sure A is one of the correct answers i’m working on the rest now
Hello!
1.
find circumferece
c=2pir
c=2*6*pi=12pi
intercept is 5.4
2pi radians=all
part/whole=part/whole
5.4/12pi=x/2pi
times both sides by 12pi
5.4=6x
divide both sides by 6
0.9=x
answer is 0.9 radians
2.
assuming 9pi/5 radians
find circumference
c=2pir
c=2*26.9*pi
c=53.8pi
arc/circumference=(9pi/5)/2pi
x/(53.8pi)=(9pi/5)/(2pi)
x/(53.8pi)=18/5
times both sides by 53.8pi
x=608.46266 m
about x=608.46 m
Hope this Helps! Have A Wonderful Day! :)
Answer:
StartFraction 1.55 over 1 EndFraction = StartFraction x over 3.5 EndFraction
Step-by-step explanation:
