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Ksenya-84 [330]

3 years ago

13

How to do this question plz answer

1 answer:

eduard3 years ago

8 0

Answer:

see below

Step-by-step explanation:

$\frac{3x^2+7x+4}{x^2+3x+2}\\\\=\frac{(3x+4)(x+1)}{(x+2)(x+1)}\\\\=\frac{3x+4}{x+2}\\\\$

and the other

$\frac{x^2-2x-8}{3x^2+7x+2}\\\\=\frac{(x-4)(x+2)}{(3x+1)(x+2)}\\\\=\frac{x-4}{3x+1}$

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