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OLga [1]
3 years ago
9

Given: g(x) = x-4 and h(x) = 2x-8. What are the restrictions on the domain of gºh? X2

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0
The answer is should be six 6
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is the problem 2 1/2 + 3 1/4 + 5/6 correct if the answer of what I got is 5 7/12 or would it be 6 7/12
aev [14]
Its gonna be 229/12, u r gonna find the lcm of the 3 denominators which is 12 and complete the work
4 0
3 years ago
Solve for 3.3x-4=-13.9
evablogger [386]

Answer: Simple and best practice solution for 3.3x-4=-13.9 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

Step-by-step explanation: Idk how to explain I’m just smart so I can figure it out

4 0
3 years ago
Read 2 more answers
3 true?<br> For what value of x is the equation<br> 2-3<br> - +4<br> À<br> B. 3<br> C. 9<br> D. -15
noname [10]

Answer:

3

Step-by-step explanation:

2 -3 = -1 + 4 = 3

4 0
3 years ago
On for the hyperbola with write an equation for the hyperbola given characteristics.
galina1969 [7]

Answer:

Step-by-step explanation:

3 0
3 years ago
Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).
vlabodo [156]
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3
5 0
3 years ago
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