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3 years ago

What is the value of the 8th term of the sequence 4, 8, 16, 32, ...?

Mathematics

2 answers:

dimaraw [331]3 years ago

7 0

Answer:

512 because

32x2=64

64x2=128

128x2=256

256x2= 512

Step-by-step explanation:

please give me brainlist

What is the value of the 8th term of the sequence 4, 8, 16, 32, ...? this is where I get 32 from

vladimir1956 [14]3 years ago

3 0

Answer:

512

Step-by-step explanation:

The sequence is doing the number times 2, so 4 times 2 equals 8,

8 x 2 = 16, ect

If you do this enough, you will get 512 as the 8th term.

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Charlotte is running at a rate of 9 KM/H.

Alex17521 [72]

Answer:

Step-by-step explanation:

$9~km/h=\frac{9 \times ~1000}{1 \times 60 \times 60}=\frac{5}{2} m/s}$

8 0

2 years ago

The coordinates of A are (1/4,3). The coordinates of B are (1/2,4.5). If the x-coordinate of C is 7/4, what is its y-coordinate

vagabundo [1.1K]

Answer:

10.5

Step-by-step explanation:

Given

A = (1/4, 3)

B = (1/2, 4.5)

To get the coordinate of C as 7/4, what was done was to first take the difference in the x coordinates and then dilate the result by 7

To get the y coordinate;

Take the difference in the coordinate

Difference = 3 - 4.5

Difference = -1.5

Dilate the result by factor of 7

This is done y multiplying the result by 7;

y coordinate = 1.5 * 7

y coordinate = 10.5

Hence its y-coordinate is 10.5

5 0

3 years ago

The mean salary offered to students who are graduating from coastal State University this year is 24245 dollars with a standard

enyata [817]

Answer:

Step-by-step explanation:

---------------

z(24750) = (27450-24260)/[3643/sqrt(85)] = 1.24007

---------------------------

P(z > 1.24007) = 10.747%

==============================

6 0

3 years ago

If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present

Brums [2.3K]

The weight of substance remaining after 13 years is 2.25 g.

Given:

Present weight of substance = 12 g

After 8 years weight remains = 6 gm

Now, weight loss in 8 year will be,

12-6=6 gm

So, weight loss in 1 year will be,

$\dfrac{6}{8} =\dfrac{3}{4}$

Total weight loss in 13 year will be,

$\dfrac{3}{4}\times13=9.75$

The weight of substance remaining after 13 years will be,

$12- 9.75 = 2.25 \;\rm g$

Therefore, the weight of substance remaining after 13 years is 2.25 g.

To know more about radioactive decay, refer to the link:

brainly.com/question/12116123

5 0

3 years ago

An endpoint of a line segment is (4,5) and the midpoint of the line segment is (3, -2). Find the other endpoint.

Dimas [21]

Answer:

(-8,1)

Step-by-step explanation:

Using the equation for midpoints we can find:

$\frac{(5+y)}{2} =3, \frac{(4+x)}{2} =-2$

$y+5=6, 4+x=-4$

$y=1, x=-8$

sry it's backwards

(-8,1)

Hope this helps!

4 0

3 years ago