Reciprocal of 2 3/11
1 answer:
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Answer:
The probability that the amount dispensed per box will have to be increased is 0.0062.
Step-by-step explanation:
Consider the provided information.
Sample of 16 boxes is selected at random.
If the mean for 1 hour is 1 pound and the standard deviation is 0.1
1 Pound = 16 ounces , then 0.1 Pound = 16/10 = 1.6 ounces
Thus: μ = 16 ounces and σ = 1.6 ounces.
Compute the test statistic
By using the table.
P value = P(Z<-250) = 0.0062
Thus, the probability that the amount dispensed per box will have to be increased is 0.0062.