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3 years ago

Describe how the graph of y=log (10 000x) is related to the graph of y=log x

1 answer:

5 0

Background: log (a . b) = log a + log b
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
= 4 + log x
therefore the graph of log(10000x) is just the graph of log x transposed by 4

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A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for wh

4vir4ik [10]

Answer:

$\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

0.16

Step-by-step explanation:

According to the question the mathematical model should be

$B(t)=2.9+0.35\sin(\dfrac{2\pi t}{5.3})$

Differentiating with respect to time we get

$B'(t)=0.35\cos(\dfrac{2\pi t}{5.3})\times(\dfrac{2\pi}{5.3})\\\Rightarrow B'(t)=\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

So, the rate of change of brightness after t days is $\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

After 1 day means $t=1$

$B'(1)=\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi\times 1}{5.3})\\\Rightarrow B'(1)=0.16$

The rate of increase after one day is 0.16.

8 0

2 years ago

8x+y=-16 -3x+y=-5 _________

Nataly [62]

Multiply the second question by -1 to cancel out the y’s. then add them. 11x=-11
x=-1
substitute that back into one of the equations
-3(-1)+y=-5
3+y=-5
y=-8

6 0

3 years ago

Read 2 more answers

|2| + |-13| = BRAINLIST AND EXTRA POINTS

kirza4 [7]

Answer:

Step-by-step explanation:

|2| + |-13| =

2+13

8 0

2 years ago

Read 2 more answers

If it takes 13 cup of flour to make 14 of a cake, how many cups of flour are needed to make a whole cake?

kvasek [131]

Answer:

Im guessing you meant it takes 1/3 cups of flour to make 1/4 of a cake not "14"

Step-by-step explanation:

in that case you would do

1/3+1/3+1/3+1/3

or 1/3*4

which would be 4/3

1 1/3

3 0

3 years ago

Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari

Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

Let X = waiting time for a car to pass by on a country road

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as 35 minutes that means $\lambda = \frac{1}{35}$ .

So, X ~ Exp( $\lambda = \frac{1}{35}$ )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

$F(x) = P(X \leq x) = 1 - e^{-\lambda x}$ , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X $\leq$ 37 min)

P(X $\leq$ 37 min) = $1 - e^{-\frac{1}{35} \times 37}$ {Using CDF}

= 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

4 0

3 years ago