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Katyanochek1 [597]
3 years ago
7

In a math test, 3/10 of the children scored an average score. what percentage scored above average?

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
3/10 so out of the 10 7 people score above average because 10-3=7 and 7+3= 10 7 and 3 make a whole please give me points and mark as brainless
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Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
If Isabella runs 23 mile each day, how many miles will Isabella run in 6 days?
Kay [80]

Answer:

138 miles

Step-by-step explanation:

23x6=138

Pls give brainliest

6 0
3 years ago
Read 2 more answers
Helppppppppp pleaseeeeeee fasttttt
topjm [15]
I think it’s 104,974
Because PEMDAS,
so first deal with exponents and 3 to the fourth power is 81. 6 to the fourth power is 1,296.
Next in PEMDAS is multiplication and division, so 1,296 times 81 is 104,976. Then 4 divided by 2 is 2.
Finally comes subtraction, 104,976 minus 2 = 104,974
5 0
3 years ago
Read 2 more answers
2. Which equation is not an example of a direct variation?
zaharov [31]
Yeshgggghhgfgggggggy. B be cc
8 0
4 years ago
The edge of each cube used to build this rectangular prism is 1/4 centimeter long. Which equation shows the volume of the prism,
ki77a [65]

Answer:

jus trynna get points

Step-by-step explanation:

5 0
3 years ago
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