Draw a diagram to illustrate the problem as shown below.
When the smaller gear rotates through a revolution, it sweeps an arc length of
2π(4) = 8π inches.
Part 1
The same arc length is swept by the larger gear. The central angle of the larger gear, x, is
7x = 8π
x = (8π)/7 radians = (8π)/7 * (180/π) = 205.7°
Answer: 205.7° (nearest tenth)
Part 2
When the larger gear makes one rotation, it sweeps an arc length of
2π(7) = 14π inches.
If the central angle for the smaller gear is y radians, then
4y = 14π
y = 3.5π radians = (3.5π)/2π revolutions = 1.75 revolutions
Answer:
The smaller gear makes 1.75 rotations
Answer:
473 yd^3
Step-by-step explanation:
The surface area of the square base is (11 yd)^2, or 121 yd^2.
The surface area of one of the slanting sides of the pyramid is
A = (1/2)(b)(h), which comes to A = (1/2)(11 yd)(16 yd) = 88 yd^2.
Thus, four such sides have a combined surface area of 352 yd^2.
Combining the surface areas of the slanting sides with the base area yields 473 yd^3
#1) Non-linear
#2) ?
#3) Linear
#4) a) linear b) linear. c) linear. d) linear
#5) ?
sorry couldn't get the rest of the answers... internet is being dumb today
Answer:
6
Step-by-step explanation:
Answer:
it was discounted by $227.85
Step-by-step explanation: