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lord [1]
3 years ago
12

Solve the exponent (2/3)^4

Mathematics
2 answers:
Goryan [66]3 years ago
8 0

Answer:

2^4/3^4=16/81

the answer is the first one

Step-by-step explanation:

split the ^4 in both numbers and remove the brackets

it will be 2^4/3^4

2^4/3^4=16/81

the answer is the first one

Licemer1 [7]3 years ago
4 0

Answer:

5 .16/81

6. 1/16

hope this helps

Step-by-step explanation:

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Points P, Q and R are collinear such that PQ : QR=2:3 point P is located at (1,3) and point R is located at (11,15)
balandron [24]

Using line segments, it is found that:

  • The coordinates of Q are (5,7.8).
  • The midpoint of segment PQ is M(6,9).

----------------------------

  • Point P is located at (1,3).
  • Point R is located at (11,15).
  • Point Q is located at (x,y).
  • PQ:QR = 2:3, which means that:

Q - P = \frac{2}{5}(R - P)

This is used to find the x and y coordinates of Q.

----------------------------

  • The <em>x-coordinate</em> of P is 1.
  • The <em>x-coordinate</em> of R is 11.
  • The <em>x-coordinate </em>of Q is x.

Thus:

Q - P = \frac{2}{5}(R - P)

x - 1 = \frac{2}{5}(11 - 1)

x - 1 = \frac{2}{5}10

x - 1 = 4

x = 5

----------------------------

  • The y<em>-coordinate</em> of P is 3.
  • The y<em>-coordinate</em> of R is 15.
  • The y<em>-coordinate </em>of Q is y.

Thus:

Q - P = \frac{2}{5}(R - P)

y - 3 = \frac{2}{5}(15 - 3)

y - 3 = \frac{24}{5}

y - 3 = 4.8

y = 7.8

The coordinates of Q are (5,7.8).

----------------------------

  • The midpoint of segment PQ is the mean of the coordinates, thus:

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The midpoint of segment PQ is M(6,9).

A similar problem is given at brainly.com/question/24148182

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