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notka56 [123]
3 years ago
7

Help ASSAP . Find the perimeter I will give you 20 points and brainlyist.

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

I think it may be 120 cm

Step-by-step explanation:

A F is 13 using pythagorean theorem on triangle CED and applying the hypotenuse length to A F.

ABC is similar to triangle CED and is dilated by a factor of 3  so the base is 36.

using pythagorean theorem on triangle ABC gets the hypotenuse length of 39 which can be applied to FE

add all the values together

39 + 13 + 15 + 36 +12 +5 = 120

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Solve the right triangle. 34.5 Find the length of the side opposite to the given angle. (Round your answer to two decimal places
lapo4ka [179]

Answer:

a) 388.03

b) 148.49

c) π/8

Step-by-step explanation:

Find the diagram attached

Let the opposite side be y

Given

a) Hypotenuse = 420

theta = 3π/8 rad

theta = 3(180)/8

theta = 67.5degrees

Using the SOH CAH TOA identity

sin theta = opposite/hypotenuse

sin 67.5 = y/420

x = 420sin67.5

x = 420(0.9238)

x = 388.03

Hence the length of the side opposite to the given angle is 388.03

b) Hypotenuse = 420

theta = 3π/8 rad

theta = 3(180)/8

theta = 67.5degrees

Using the SOH CAH TOA identity

cos theta = adjacent/hypotenuse

cos 67.5 = x/420

x = 420cos67.5

x = 420(0.3827)

x = 148.49

Hence the length of the side adjacent to the given angle is 148.49

c) The sum of angle in the triangle is π

Let the measure of the unknown angle be z

z + 3π/8 + π/2 = π

z + 3π+4π/8 = π

z + 7π/8 = π

z = π - 7π/8

z = (8π-7π)/8

z = π/8

Hence the measure of the other acute angle is π/8

5 0
2 years ago
Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar
yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.  

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

<em>Let </em>\mu_1<em> = true mean number of sales at location A.</em>

<em />\mu_2 = <em>true mean number of sales at location B</em>

So, Null Hypothesis, H_0 : \mu_1-\mu_2\geq0  or  \mu_1 \geq \mu_2     {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, H_A : \mu_1-\mu_2  or  \mu_1< \mu_2    {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                        T.S. =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t_n__1_-_n__2-2

where, \bar X_1 = sample average of items sold at location A = 39

\bar X_2 = sample average of items sold at location B = 49

s_1 = sample standard deviation of items sold at location A = 8

s_2 = sample standard deviation of items sold at location B = 4

n_1 = sample of days location A was observed = 18

n_2 = sample of days location B was observed = 13

Also,  s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }  = \sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2}  }{18+13-2} }  = 6.64

So, <u><em>test statistics</em></u>  =  \frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13}  } }  ~ t_2_9  

                               =  -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

<em>Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0
3 years ago
A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, thi
Mice21 [21]

Answer:

4(2+\sqrt{2})\text{ square unit}

Step-by-step explanation:

Given function that shows the area of the opening,

A(\theta)=16 \sin\theta (\sin \theta + 1)

If \theta = 45^{\circ}

Hence, the area of the opening would be,

A(45^{\circ})=16 \sin 45^{\circ} (\cos 45^{\circ} + 1)

=16\times \frac{1}{\sqrt{2}}\times (\frac{1}{\sqrt{2}}+1)

=16(\frac{1}{2}+\frac{1}{\sqrt{2}})

=8+\frac{16}{\sqrt{2}}

=8+4\sqrt{2}

=4(2+\sqrt{2})\text{ square unit}

7 0
3 years ago
If 5x = b and b = -45, what is x?
anzhelika [568]
X=-9. just divide 45 and 5
6 0
2 years ago
Work out <br> -11x = 220<br> x= ?
irina1246 [14]

Answer:

<h2>-20</h2>

Step-by-step explanation:

divide both by -11 ->

x  = - 20

3 0
3 years ago
Read 2 more answers
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