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KATRIN_1 [288]
3 years ago
10

Ln(x-5)-ln(x-4)=-2 Please help solve

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0
X-5/ X-4=. e^-2
-4+5e^2 / e^2-1

Or ≈ 5.15652
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While working at his neighborhood math tutoring center researching the comprehension level of the students Dion investigated tha
elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

While working at his neighborhood math tutoring center researching the comprehension level of the students Dion investigated that the distribution of the student test scores are normally distributed with a mean of 79.13 and a standard deviation of 6.34. What is the probability that the student scores less than 60.11

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

z = 60.11 - 79.13/6.34

6 0
3 years ago
Sales= 768. comission rate= 4%. comission rate= ?
Marizza181 [45]

Answer: Commission rate = $30.72

Step-by-step explanation: For this problem we want to find the commission rate for sales that are a total of $768. The commission rate is 4%.

Convert 4% to a decimal. 4/100 = 0.04.

Now, multiply the sales by the decimal 0.04 to find the commission rate.

768 x 0.04 = 30.72, or $30.72 for the commission rate.

5 0
4 years ago
What is the real part of 4-5i<br><br>a. 5<br><br>b. 4<br><br>c. -5i<br><br>d. -5<br><br>PLEASE HELP!
marysya [2.9K]

Answer:

<h2>4</h2>

Step-by-step explanation:

A complex number in its rectangular form is expressed as x+iy where x is the real part of the complex number and y is the imaginary because it is attached to the imaginary number i.

Given the complex number 4-5i, comparing the complex number with x+iy

4 = x and iy = -5i

Hence x = 4 and y = -5.

Since x is the real part of the complex number x+iy,<em> hence 4 will be the real part of the complex number 4-5i based on comparison. </em>

7 0
4 years ago
A music industry researcher wants to estimate, with a 90% confidence level, the proportion of young urban people (ages 21 to 35
Maslowich

Answer:

1,539

Step-by-step explanation:

Using Simple Random Sampling in an infinite population (this is such a large population that we do not know the exact number) we have that the sample size should be the nearest integer to

\large \frac{Z^2pq}{e^2}

where

<em>Z= the z-score corresponding to the confidence level, in this case 90%, so Z=1.645 (this means that the area under the Normal N(0,1) between [-1.645,1.645] is 90%=0.9) </em>

<em>p= the proportion of young urban people (ages 21 to 35 years) who go to at least 3 concerts a year= 35% = 0.35 </em>

<em>q = 1-p = 0.65 </em>

<em>e = the error proportion = 2% = 0.02 </em>

Making the calculations

\large \frac{Z^2pq}{e^2}=\frac{(1.645)^2*0.35*0.65}{(0.02)^2}=1,539.09

So, the sample size should be 1,539 young urban people (ages 21 to 35 years)

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3 years ago
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