Answer:

Step-by-step explanation:
we know that
Applying the Intersecting Secant Theorem

substitute the values

Solve for ED



Answer:
a = 3 7/18 or 3.388889
Step-by-step explanation:
First, you want to get the a by itself, so you would subtract 4 from the left side of the equals sign.
6a + 4 = 61 / 3 + 4
-4 -4
6a = 61 / 3
By doing that, they cancel each other out, so you are left with
6a = 61 / 3
Then you want to get a by itself, so you divide 6 from both sides.
6a / 6 = 61 / 3 / 6
Remember that 6 can also be written as 6/1
Remember that dividing a fraction is multiplying the reciprocal.
6a / 6 = 61 / 3 / 6 / 1
When dividing fractions remember to Skip the first fraction, Flip the second fraction, and Multiply the two fractions together.
61 / 3 x 1 / 6
skip multiply flip
Multiply across the top, and across the bottom.
61(1) and 3(6)
Then you get
61 / 18
So a = 61 / 18
If you want to convert that to a mixed number, it would be 3 7 / 18
If you want that in a decimal, it would be 3.388889
Answer:
5 i think
Step-by-step explanation:
I'm not sure you finished the question because there isn't an x there but I simplified it in case that's what you wanted
2 + 6 = 8
4 - 3 = 1
8(1) = 8
8 = 8
Answer:
The cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95
Step-by-step explanation:
A linear function is a polynomial function of the first degree that has the following form:
y= m*x + b
where
- m is the slope of the function
- n is the ordinate (at the origin) of the function
So, in this case: C(x)= m*( x-1990) + b where x is the number of years since 1990.
Given the coordinates of two points, it is possible to determine the slope m of the line from them using the following formula:

In this case, you know that in 1990, the cost of tuition at a large Midwestern university was $95 per credit hour. And in 1999, tuition had risen to $221 per credit hour. So:
- x1= 1990
- y1= 95
- x2= 1999
- y2= 221
So the value of m is:


m= 14
So C(x)= 14*( x-1990) + b. In 1999, tuition had risen to $221 per credit hour. Replacing:
221= 14*(1999 - 1990) + b
221= 14*9 +b
221= 126 + b
221 - 126= b
95= b
Finally, <u><em>the cost of tuition as a function of x, the number of years since 1990, is C(x)= 14*(x-1990) + 95</em></u>