The vertex of the function is (-6,-36).
<u>Step-by-step explanation:</u>
f(x) = x²+ 12x
From the above function, we can find the x- coordinate of the vertex as,
x = -b/2a
Here a = 1, b = 12
Plugin the values as,
x = -12 /(2×1) = -6
Now plug in the x value in the above function, we will get y as,
f(x) = y = x² + 12x = (-6)² + 12(-6)
= 36-72 = -36
So the vertex is (-6, -36).
Answer:
The parabola's axis of symmetry is x = -6
Step-by-step explanation:
Parabola general equation:
y = a*(x - r1)*(x - r2)
Equation given:
y = (-1/4)*(x + 2)*(x + 10)
a = -1/4
r1 = -2
r2 = -10
To check if the parabola passes through the point (2, 10) it is necessary to replace x = 2 and check the y-value, as follows:
y = (-1/4)*(2+ 2)*(2 + 10) = -12
Then, point (2, 10) is not included in the parabola.
If a > 0 then the parabola opens upward; if a < 0 then the parabola opens downward. Then, the parabola opens downward
Axis of symmetry:
h = (r1 + r2)/2
h = (-2 + -10)/2 = -6
Then, The parabola's axis of symmetry is x = -6
To find Parabola's vertex, replace with the axis of symmetry:
y = (-1/4)*(-6 + 2)*(-6 + 10) = 4
Therefore, the parabola has a vertex at (-6, 4)
2x+7
is the simplest form
Answer:
equation: y = 4x-12
slope: 4
y-intercept: -12
Step-by-step explanation:
3 points across an x-axis is +1 x-axis difference and +4 y-axis away from origin, so you have to subtract 3 by 1 andsubtract y by 4. until x is 0, you get -12 on y-axis
Answer:
option c
Step-by-step explanation:
