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grigory [225]
3 years ago
11

Help if you can!! I really need some good grades or I will fail this and that wont help anything.

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

26) A

29)D

4) C

Step-by-step explanation:

Hope this helps. Your gonna pass

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Round 3.721 to the nearest hundredths place
kirill [66]
3.700

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5 0
3 years ago
If the height of a triangle
Dvinal [7]

Answer:

75 cm

Step-by-step explanation:

To find the area of a traingle you use the following equation

b*h*.5

We know that the height of the triange is three times the base and that the area is 937.5

This means that

b*3b*.5=937.5

We can combine this and get 1.5b^2=937.5

We can then divide by 1.5 to get b by itself

b^2=625

Then take the square root for our answer and get b=25 (while be also can be -25 it doesn't make sense to have a negative answer in the context of this problem)

So we know that b=25 and that h=3b which means that the height is 75 cm

5 0
3 years ago
This graph shows a proportional relationship.
xxMikexx [17]

Step-by-step explanation:

what u suppose to do on this work, reply quickly so I can help

4 0
3 years ago
Read 2 more answers
Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x.<br><br> show your work
aliya0001 [1]

Answer:

x=14

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

ON≅QR

corresponding angles

∠M≅∠P

∠O≅∠Q

∠N≅∠R

therefore

MN=PR

substitute the given values

32=3x-10

solve for x

3x=32+10

3x=42

x=14

3 0
3 years ago
X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
2 years ago
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