Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
To find the rate of change find the difference in the Y values for every X value.
From X 1 to X 3 the Y value changes by -10
-10 / 2 = -5.
The rate of change is -5.
The initial value is when X = 0
When X is 1, the Y value is 20, using the rate of change of -5, this means when X is 0, the Y value would be 25.
The answer would be, the initial value is 25, rate of change is -5
Answer A would the one that's false
H= .6.5
V=<span>πr^2h
h= v/</span>πr^2 = 2940.5/<span>π*12^2 = 6.49993 = 6.5</span>