Which conversions from scientific notation to standard notation are true? Select the four correct answers
1 answer:
The options are missing, so i have attached them.
Answer:
options B, E, G & H are correct.
Step-by-step explanation:
A) We are given;
1.71 × 10³ = 0.00171
For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point to the right of 1.71 three times because the exponent is 3.
Thus, the proper conversion is;
1.71 × 10³ = 1710
B) We are given;
8.05 × 10^(5) = 805000
For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 8.05 because the exponent is 5.
Thus, the proper conversion is;
8.05 × 10^(5) = 805000
C) We are given;
2.4 × 10⁴ = -24000
For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point four times to the right of 2.4 because the exponent is 4.
Thus, the proper conversion is;
2.4 × 10⁴ = 24000
D) We are given;
8.25 × 10^(-3) = -8250
For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point three times to the left of 8.25 because the exponent is -3.
Thus, the proper conversion is;
8.25 × 10^(-3) = 0.00825
E) We are given;
7.09 × 10^(-6) = 0.00000709
For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point six times to the left of 7.09 because the exponent is -6.
Thus, the proper conversion is;
7.09 × 10^(-6) = 0.00000709
F) We are given;
3.99 × 10^(5) = 300,099
For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 3.99 because the exponent is 5.
Thus, the proper conversion is;
3.99 × 10^(5) = 399,000
G)We are given;
8 × 10^(7) = 80,000,000
For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point seven times to the right of 8 because the exponent is 7.
Thus, the proper conversion is;
8 × 10^(7) = 80,000,000
H) We are given;
1.03 × 10^(-4) = 0.000103
For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point four times to the left of 1.03 because the exponent is -4.
Thus, the proper conversion is;
1.03 × 10^(-4) = 0.000103
Looking at all the options as well as the proof I got, only options B, E, G & H are correct.
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The piecewise functions that are represented by the graph are; g(x) = −2, x < −2; g(x) = −2x + 6, x ≥ 1; g(x) = x/2 + 1, –2 ≤ x < 1
<h3>How to Interpret a Piecewise Function graph?</h3>From the attached graph of the piecewise function, we can access each option as follows;
A) g(x) = −2x, −2 < x < 0
This is not represented by the graph because g(x) = −2x has negative slope which means it goes downward. There's also no y-intercept in g(x) = −2x.
B) g(x) = −2, x < −2;
This is represented by the graph because g(x) = −2 is a horizontal line which is only on the left side of x = -2.
C) g(x) = x − 2, −2 < x < 1;
This is not represented by the graph because g(x) = x − 2 has y-intercept at y = -2 and slope of 1 which means that graph of g(x)= x - 2 must be going upward and crossing at y = -2.
D) g(x) = −2x + 6, x ≥ 1
This is represented by the graph because g(x) = −2x+6 satisfies the graph which is going downward.
E) g(x) = x/2 + 1, –2 ≤ x < 1
This is represented by the graph because g(x) = (x/2) + 1 satisfies the graph which is going downward.
The options are;
g(x) = −2x, −2 < x < 0
g(x) = −2, x < −2
g(x) = x − 2, −2 < x < 1
g(x) = −2x + 6, x ≥ 1
g(x) = x/2+ 1, –2 ≤ x < 1
Read more about Piecewise Function at; brainly.com/question/3628123
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