Round 287.63 to the nearest whole number.

Mathematics

1 answer:

Sedbober [7]2 years ago

6 0

The answer would be 288 to the nearest whole number

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If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

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maxonik [38]

Answer:

Option C is correct.

$38 miles$