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FromTheMoon [43]
3 years ago
14

The area of a rectangle is 60 cm2 If the width of the

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

The length of the rectangle is 10 cm and perimeter of the rectangle is 32 cm.

Step-by-step explanation:

Given,

The area of rectangle = 60 sq cm

Width (b) of the rectangle = 6 cm

To find the length and perimeter of the rectangle.

Formula

The area of the rectangle = l×b

The perimeter of the rectangle = 2(l+b)

According to the problem,

l×b = 60

or, l×6 = 60

or, l = 60÷6 = 10

Length (l) = 10 cm

Perimeter = 2×(10+6) cm = 32 cm

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How many ways can you give 18 cards to 2 people
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Let X ~ N(0, 1) and Y = eX. Y is called a log-normal random variable.
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If F_Y(y) is the cumulative distribution function for Y, then

F_Y(y)=P(Y\le y)=P(e^X\le y)=P(X\le\ln y)=F_X(\ln y)

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The nth moment of Y is

E[Y^n]=\displaystyle\int_{-\infty}^\infty y^nf_Y(y)\,\mathrm dy=\frac1{\sqrt{2\pi}}\int_0^\infty y^{n-1}e^{-\frac12(\ln y)^2}\,\mathrm dy

Let u=\ln y, so that \mathrm du=\frac{\mathrm dy}y and y^n=e^{nu}:

E[Y^n]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu}e^{-\frac12u^2}\,\mathrm du=\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty e^{nu-\frac12u^2}\,\mathrm du

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so we end up with

E[Y^n]=e^{\frac12n^2}

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