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fenix001 [56]
2 years ago
6

Solve the simultaneous equation 2x+4y=1 3x+5y=7b

Mathematics
1 answer:
Lyrx [107]2 years ago
8 0

Step-by-step explanation:

  • 3x+5y=7b equation 1
  • 2x+4y=1

2x=-4y+1

  • x=(-4y+1)/2
  • x=(-4y+1)/2 in equation 1

3×(-4y+1)/2+5y=7b

(-12y+3)/2+5y=7b

(-12y+3+10y)/2=7b

(-12y+3)/2=7b

-12y+3=14b

-12y=14b-3

  • y=3-14b/12
  • y=3-14b/12 in x=(-4y+1)/2

x=(-4×{3-14b/12}+1)/2

x=(-3+14b)/3+1/2

x=14b/3×1/2

  • x=7b/3
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A sample is BEST defined as _________.
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Answer:

(B) A selected group of participants that is representative of a larger population

Step-by-step explanation:

A sample statistic is a piece of information that you get from a fraction of the population. This information is representative of a larger population.

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So, the correct answer is:

(B) A selected group of participants that is representative of a larger population

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3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
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Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

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0.5\sqrt{n} = 2*1.96

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(\sqrt{n})^2 = (4*1.96)^2

n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

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