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jenyasd209 [6]
3 years ago
12

Help

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
Can you post this and provide a picture please so I can help you ?

Explanation:
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How to solve this math problem step by step tell me how to do it. I need to know to do it instead giving me the answer. A fracti
stiv31 [10]

Answer: 9/15 or 3/5

Step-by-step explanation:

This is world problems leading to the linear equation.

Now listen, in a fraction, a/b where a = numerator and b = denominator

Now let the denominator = x and the denominator = x + 4 since the denominator is four greater than the the numerator.

From the question, the value of the fraction = 9/15 or 3/5 in its lowest term.

Now to get the fraction,

Organise the fraction base on the statements above

x

------ , now equate it to 9/15 of 3/5

x + 4

in it's lowest term.

x/x +4. = 9/15

x. 9

------- = -----

x + 4. 15

Now convert it to a linear expression by cross multiply

15x = 9( x + 4 ), now solve for x by opening the bracket by multiplying through by 9, and collect like terms.

15x = 9x + 36

15x - 9x = 36

6x = 36

x = 6.

Therefore, substitute for those values in the fraction above

x 6. 6. 3

------ = ------- = ------ = ----

x + 4 6 + 4. 10. 5

Now the original fraction is

9/15 or 3/5 ( 3 is a common factor to both the numerator and the denominator )

Just go through it step by step bearing the explanation in mind.

4 0
3 years ago
Find the scale factor of the dilation. Then tell whether the dilation is a reduction or an enlargement.
steposvetlana [31]
P is the scale factor
3 0
2 years ago
The fish population is decreasing at a rate of 3% per year. In 2002 there were about 2100 fish. Find the fish population in 2010
djyliett [7]

Answer:

Population of fish in 2010 = 1,646 fish (Approx.)

Step-by-step explanation:

Given:

Population of fish in 2002 = 2100 fish

Decrease rate = 3% per year

Find:

Population of fish in 2010

Computation:

Number of year = 2010 - 2002

Number of year = 8 year

A = P[1+r]ⁿ

Population of fish in 2010 = Population of fish in 2002[1+(-3%)]ⁿ

Population of fish in 2010 = 2100[1-0.03]⁸

Population of fish in 2010 = 2100[0.97]⁸

Population of fish in 2010 = 2100[0.7837]

Population of fish in 2010 = 1645.77

Population of fish in 2010 = 1,646 fish (Approx.)

4 0
3 years ago
(someone help)
madam [21]

Answer:

600 and 3

Step-by-step explanation:

8 0
2 years ago
The number of men and women receiving bachelor's degrees each year has been steadily increasing. For the years 1970 through the
UkoKoshka [18]

Answer:

the answer is A

4 0
3 years ago
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