The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
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If you are comparing the triangles the answer is D
Answer:
, all integers where n≥1
Step-by-step explanation:
we know that
The explicit equation for an arithmetic sequence is equal to
a_n is the th term
a_1 is the first term
d is the common difference
n is the number of terms
we have

Remember that
In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference.
To find out the common difference subtract the first term from the second term

substitute the given values in the formula

The domain is all integers for 