HELP ASASP PLEASE!!!!!!! What is the following simplified product? Assume x>/0

Mathematics

2 answers:

luda_lava [24]3 years ago

6 0

Answer: Third option.
Please, see the detailed solution in the attache file.
Thanks

jeyben [28]3 years ago

3 0

Answer:

Option 3 is correct answer i.e., $3x\sqrt{6x}-x^4\sqrt{30x}+24x^2\sqrt{2}-8x^5\sqrt{10}$

Step-by-step explanation:

Given: $(\sqrt{6x^2}+4\sqrt{8x^3})(\sqrt{9x}-x\sqrt{5x^5})$

This Product is simplified using Polynomial Product of Binomial with Binomial.

Following are steps of Product:

$(\sqrt{6x^2}+4\sqrt{8x^3})(\sqrt{9x}-x\sqrt{5x^5})$

⇒ $(x\sqrt{6}+4\sqrt{4.2.x^2.x})(3\sqrt{x}-x\sqrt{5.x^4.x)}$

⇒ $(x\sqrt{6}+8x\sqrt{2x})(3\sqrt{x}-x^3\sqrt{5x)}$

⇒ $(x\sqrt{6})(3\sqrt{x})+(x\sqrt{6})(-x^3\sqrt{5x})+(8x\sqrt{2x})(3\sqrt{x})+(8x\sqrt{2x})(-x^3\sqrt{5x})$

⇒ $x.3\sqrt{6.x}+(-x.x^3\sqrt{6.5.x})+3.8x\sqrt{2x.x}+(-8x.x^3\sqrt{2x.5x})$

⇒ $x3\sqrt{6x}-x^4\sqrt{30x}+24x\sqrt{2.x^2}-8x^4\sqrt{10.x^2}$

⇒ $x3\sqrt{6x}-x^4\sqrt{30x}+24x.x\sqrt{2}-8x^4.x\sqrt{10}$

⇒ $3x\sqrt{6x}-x^4\sqrt{30x}+24x^2\sqrt{2}-8x^5\sqrt{10}$

This Matches with Option 3.

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pshichka [43]

Answer:

Step-by-step explanation:

Perpendicular means that the slopes of the "old" line and the "new" line are opposite reciprocals; bisector means that the "new" line goes directly through the center of the "old" line. This perpendicular bisector, then, will go directly through the center of the "old" line, cutting it directly in half and leaving in its wake a 90 degree angle. To write this equation, then, of the perpendicular bisector, we need the slope of the old line and the midpoint of the old line. Let's work on the midpoint first:

$M=(\frac{3+6}{2},\frac{5-7}{2})\\M=(\frac{9}{2},\frac{-2}{2})\\M=(\frac{9}{2},-1)$ So the "new" line will go through this point.