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4 years ago

7

When csc(Theta)sin(Theta) is simplified, what is the result? StartFraction 1 Over cosecant squared EndFraction StartFraction 1 O

ver sine squared EndFraction 0 1

1 answer:

const2013 [10]4 years ago

6 0

Step-by-step explanation:

csc θ sin θ

(1 / sin θ) sin θ

1

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There are 20 female performers in a dance recitial. The ratio of men to women is 3;4 . How many men are in the dance recitial.

Triss [41]

Answer:

There are 15 men in the dance recital.

Step-by-step explanation:

If 20 people is 4 parts, then 5 people are 1 part. Due to that, 15 people will equal 3 parts.

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3 years ago

Whats the difference between "6 + A" and "6 x A"

Nata [24]

Answer:

To determine what is the difference between "6 + A" and "6 x A", the logic of the proposed mathematical operations must be explained:

In "6 + A", the value A is added to the initial value 6. Thus, for example, if A were worth 10, to the initial value 6 10 units are added, with which the final value is 16.

In contrast, in "6 x A", the initial value 6 is multiplied by as many times as the value A indicates. Therefore, continuing with the value of A as 10, in this case 6 would be multiplied by 10 times, giving a final value of 60.

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3 years ago

There are 3 balls in a hat; one with the number 1 on it, one with the number 6 on it, and one with the number 7 on it. You

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Answer:

coin: ball:

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3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

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3 years ago

A system of two equations is shown.

Delvig [45]

Answer:

x=-2;y=-7

Step-by-step explanation:

y=5x+3

y=3x-1

3x-1=5x+3

-2x=4

x=-2 y=5x+3 y=5×(-2)+3 y=-7

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3 years ago