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Igoryamba
4 years ago
7

When csc(Theta)sin(Theta) is simplified, what is the result? StartFraction 1 Over cosecant squared EndFraction StartFraction 1 O

ver sine squared EndFraction 0 1
Mathematics
1 answer:
const2013 [10]4 years ago
6 0

Step-by-step explanation:

csc θ sin θ

(1 / sin θ) sin θ

1

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Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7
marusya05 [52]

Answer:

  • -3x² -5x -1 = 0
  • -3 (quadratic)
  • -5 (linear)
  • -1 (constant)

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

  -3x² -8 -(5x -7) = 5x -7 -(5x -7)

  -3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

  -3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

  -3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

__

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

  3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

8 0
2 years ago
Which equation can be used to solve for m∠1? m∠1 = One-half(a – b) m∠1 = One-half(a + b) m∠1 = One-half(c – d) m∠1 = One-half(c
Artemon [7]

Answer:

m\angle 1=\frac{1}{2}(arc\ a+arc\ b)

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The measure of the<u><em> interior angle</em></u> is the semi-sum of the arches that comprise it and its opposite.

so

m\angle 1=\frac{1}{2}(arc\ a+arc\ b)

8 0
3 years ago
Read 2 more answers
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