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earnstyle [38]
3 years ago
8

NEED HELP ASAP TAKING TEST-On average, a person’s body temperature should be approximately 98.6°F. A doctor would like to test t

he hypotheses H Subscript 0 Baseline: mu = 98.6 versus H Subscript alpha Baseline: mu not-equals98.6 where μ = the true mean body temperature of all adults. Before conducting the test, the doctor determines that the power of the test to reject the null hypothesis when μ = 98 using α = 0.01 and n = 10 is 0.2474. What combination of sample size and significance level would increase the power of this test the most?
use n = 5, alpha = 0.05
use n = 5, alpha = 0.10
use n = 20, alpha = 0.05
use n = 20, alpha = 0.10
Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

D I think,

Step-by-step explanation:

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The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

  • The mean is-

\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5

  • The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

  • The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

  • The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

r=97-41\\r=56

  • The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

IQR=63-23\\IQR=20

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

#SPJ1

4 0
2 years ago
If anyone downto zo0m...uhh...here yah go...<br> Meeting ID: 849 0344 3500<br> Passcode: 1EeRuj
andreev551 [17]

what are we suppose to do?

3 0
3 years ago
Solve:​ z5 + 3 = −35
Fudgin [204]

Answer:

z= - 5 √ 38

Step-by-step explanation:

take the root of both sides

or

you can factor each set and make them equal to zero

8 0
4 years ago
A sphere with a radius of 5 cm fits inside a box. Every face of the box is tangent to the sphere. What is the ratio of the volum
BARSIC [14]
Volume of box with side length of 5 = 5^3 = 125

Volume of sphere = (4/3)*pi*5^3 = (4/3)pi * 125

Ratio = 125/(4pi/3)*125  = 1/(4pi/3) = 3/(4pi)

Answer: B
8 0
3 years ago
Read 2 more answers
Help me pls this is urgent ;&gt;
postnew [5]

Answer:

\frac{ |a + x| }{2}  -  \frac{ |a - x| }{2}  \\  \\  =  \frac{ | - 2 - 6| }{2}  -  \frac{ | - 2 + 6| }{2}  \\  \\  =  \frac{ | - 8| }{2}  -  \frac{ |4| }{2}  \\  \\  =  \frac{8}{2}  -  \frac{4}{2}  \\  \\  = 4 - 2 = 2

5 0
3 years ago
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