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3 years ago

What happens when a rational number is added to an irrational number

Mathematics

1 answer:

Whitepunk [10]3 years ago

6 0

The answer to your question is,

Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.

-Mabel <3

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Ay help its easy pleaseeee.

pickupchik [31]

Answer:

425ft.

Step-by-step explanation:

Just add 395 and 30 together.

Hope this helps. Pls give brainliest!

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2 years ago

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Help me plz it’s due today

Serggg [28]

Answer:

Step-by-step explanation: Your salary will be greater than or equal to $46,000.

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3 years ago

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The blueprint of a fishing pier uses a scale of 1/8 inch = 5 feet. If the pier is 3 19/4 inches long on the blueprint, find its

poizon [28]

Answer:

190

Step-by-step explanation:

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4 0

3 years ago

Need the answers to these questions please

Katena32 [7]

Answer:

a) $p = 88\,cm$ , b) $p = 24\,cm$ , c) $p \approx 25.424\,m$ , d) $p \approx 39.368\,cm$

Step-by-step explanation:

a) The perimeter is the sum of the three sides of the internal square and the remaining sides of the external rectangle, that is:

$p = 3\times 8\,cm + 2\times 4\,cm +2\times 20\,cm + 16\,cm$

$p = 88\,cm$

b) The perimeter is the sum of the two sides of the internal triangle and the remaining sides of the external rectangle, that is:

$p = 2\times 4\,cm + 2\times 6\,cm + 4\,cm$

$p = 24\,cm$

c) The perimeter is the sum of the two sides of the circular section and the three sides of the lower rectangle, that is:

$p = \frac{\pi}{2}\times 6\,cm + 8\,cm + 6\,cm + 2\,cm$

$p \approx 25.424\,m$

d) The perimeter is the sum of the external sides of the triangle and rectangle, that is:

$p = 10\,cm + 12\,cm + 12\,cm + 12\,cm - \sqrt{(12\,cm)^{2}-(10\,cm)^{2}}$

$p \approx 39.368\,cm$

5 0

3 years ago

Show all work below to answer the following for a certain city that had a population of 150,000 in the year 2010. In 2020, the p

Gelneren [198K]

The constant rate of continuous growth, k, for this population is equal to 2.11935%. And the population will reach 250,000 people in 24.36 years.

For solving this question, you should apply the Population Growth Equation.

<h3>Population Growth Equation</h3>

The formula for the Population Growth Equation is:

$P_f=P_o*(1+\frac{R}{100} )^t$

Pf= future population

Po=initial population

r=growth rate

t= time (years)

STEP 1 - Find the constant rate of continuous growth, k, for this population.

For this exercise, you have:

Pf= future population= 185,000 in 2020.

Po=initial population =150,000 in 2010.

r=growth rate= ?

t= time (years)=2020-2010=10

Then,

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 185000=150000\cdot \left(1+\frac{R}{100}\:\right)^{10}\\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{185000}{150000} \\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{37}{30}\\ \\ R=100\sqrt[10]{\frac{37}{30}}-100=2.11935\%$

STEP 2 - Find the <em>t</em> for population 250,000 people.

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 250000=150000\cdot \left(1+\frac{2.11935}{100}\:\right)^{10}\\ \\ \left(1+\frac{2.11935}{100}\right)^{10}=\frac{250000}{150000} \\ \\ \left(1+\frac{2.11935}{100}\right)^t=\frac{5}{3}\\ \\ t\ln \left(1+\frac{2.11935}{100}\right)=\ln \left(\frac{5}{3}\right)\\ \\ t=\frac{\ln \left(\frac{5}{3}\right)}{\ln \left(\frac{102.11935}{100}\right)}\\ \\ t=24.36$

Read more about the population growth equation here:

brainly.com/question/25630111

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2 years ago