you would do PEMDAS
you do -3 times 4. then you do that and devide by -3.
Answer with Step-by-step explanation:
We are given that
RHS
![\frac{1+Cos2x}{Sin2x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%2BCos2x%7D%7BSin2x%7D)
We have to verify the identity.
We know that
![1+Cos2x=2Cos^2 x](https://tex.z-dn.net/?f=1%2BCos2x%3D2Cos%5E2%20x)
![Sin2x=2SinxCos x](https://tex.z-dn.net/?f=Sin2x%3D2SinxCos%20x)
Using the formula
![\frac{2Cos^2x}{2SinxCosx}](https://tex.z-dn.net/?f=%5Cfrac%7B2Cos%5E2x%7D%7B2SinxCosx%7D)
![\frac{Cosx}{Sinx}](https://tex.z-dn.net/?f=%5Cfrac%7BCosx%7D%7BSinx%7D)
![Cot x](https://tex.z-dn.net/?f=Cot%20x)
By using the formula
![Cotx=\frac{Cosx}{Sinx}](https://tex.z-dn.net/?f=Cotx%3D%5Cfrac%7BCosx%7D%7BSinx%7D)
LHS=RHS
Hence, verified
It would take the bud 15 minutes to travel at 125
Answer:
x = ±5
Step-by-step explanation:
4x^2 = 100
Divide each side by 4
4/4x^2 = 100/4
x^2 = 25
Take the square root of each side
sqrt(x^2) = ±sqrt(25)
x = ±5
Answer:
Angle of elevation from Kim to the satellite launch = 6.654°
Step-by-step explanation:
The distance from Kim to the satellite launch
= 6 miles
Height of the satellite launch
= 0.7 miles
Angle of elevation from Kim to the satellite launch = b
Tan b = height of satellite/distance from Kim
Tan b= 0.7/6
Tan b= 0.1166667
b = tan^-1 (0.1166667)
b= 6.654°
Angle of elevation from Kim to the satellite launch = 6.654°