Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
f^-1(x) = -1/8x +1/4
Step-by-step explanation:
To find the inverse of a function
Exchange x and y and then solve for y
y =-8x+2
Exchange x and y
x = -8y+2
Now solve for y
Subtract 2 from each side
x-2 = -8y+2-2
x-2 = -8y
Divide by -8
(x-2)/-8 = -8y/-8
Distribute
-1/8x +1/4 = y
f^-1(x) = -1/8x +1/4
D
Because it is one of the parent functions
