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3 years ago

Need help right now!!!!!!

Mathematics

2 answers:

Reptile [31]3 years ago

8 0

Answer:

44.75

I believe

Sonja [21]3 years ago

7 0

Let's go:

$\frac{21}{36} = \frac{3x + 1}{6x - 6} \\\\ 36(3x + 1) = 21(6x - 6) \\\ 108x + 36 = 126x - 126 \\\ 126x - 108x = 36 + 126 \\\ 18x = 162 \\\ x = 9$

I hope I helped you.

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A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage

fiasKO [112]

We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

$\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}$

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

$RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}$

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

$RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}$

For grade C:

$RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}$

For grade D:

$RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}$

For grade F:

$RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}$

4 0

1 year ago

If u subtract 17 from my number and multiply the difference by -7, the result is -35.What is my number

Kryger [21]

Let x = your number.

(x - 17) * -7 = -35. Divide each side by -7.

(x - 17) = 5. Add 17 to each side.

x = 22.

Your number is 22

5 0

3 years ago

Read 2 more answers

Please answer giving Brainliest

yarga [219]

I can’t find the answer. Are you sure this is the whole question?

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1 year ago

Didn’t learn this good

patriot [66]

.059, you move the decimal point two times to the left and the other way around when you want to convert into a percent

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3 years ago

A van travels at a constant speed of x km/hr over a distance of 45km/hr. If the van increases its speed by 4km/h, it will be abl

harkovskaia [24]

Speed = Distance/Time. Let speed be V, distance D and time T

a)Given: D₁ =45km, V₁=x km/h
V₁=D₁/T
V₁=45/T OR T= 45/V₁

b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:

V₁+4 = 48/T OR T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁

3V₁ =180 and V₁ = x = 60 km/h

8 0

3 years ago