Let's say "p" people were going to the expedition initially, and the cost for each was "c", now, we know the total cost is 1800, so for "p", folks that'd be 1800/p how much each one cost, namely, how many times "p" goes into 1800.
well, prior to leaving, 15 dropped out, so that leaves us with " p - 15 ", and the cost "c" bumped up to " c + 27 " for each.

![\bf 1800p=1800(p-15)+27[p(p-15)] \\\\\\ 1800p=1800p-27000+27(p^2-15p) \\\\\\ 0=-27000+27(p^2-15p)\implies 0=-27000+27p^2-405p \\\\\\ \textit{now, let's take a common factor of }27 \\\\\\ 0=p^2-15p-1000\implies 0=(p-40)(p+25)\implies p= \begin{cases} \boxed{40}\\ -25 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%201800p%3D1800%28p-15%29%2B27%5Bp%28p-15%29%5D%0A%5C%5C%5C%5C%5C%5C%0A1800p%3D1800p-27000%2B27%28p%5E2-15p%29%0A%5C%5C%5C%5C%5C%5C%0A0%3D-27000%2B27%28p%5E2-15p%29%5Cimplies%200%3D-27000%2B27p%5E2-405p%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bnow%2C%20let%27s%20take%20a%20common%20factor%20of%20%7D27%0A%5C%5C%5C%5C%5C%5C%0A0%3Dp%5E2-15p-1000%5Cimplies%200%3D%28p-40%29%28p%2B25%29%5Cimplies%20p%3D%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7B40%7D%5C%5C%0A-25%0A%5Cend%7Bcases%7D)
well, you can't have a negative value of people... so it has to be 40.
so, 40 folks were initially going, then 15 dropped out, how many went on the expedition? 40 - 15.
I hope and think it’s 12015
Because this what I did I (.89)x
And x = 13500 and I got 12015
He gets an average between 80 and 90
It is between these two values
So it could be 80 or higher but it must be 90 or belowe so it can be equal to 80 or above and it can be equal to 90 or below
This gives two inequalities 80 ≤ x and x ≤ 90
This can be written as 1 inequality 80 ≤ x ≤ 90
≤ this means less than or equal to the one that points the opposite way would be greater than or equal to think of it as a number line pointing right is positive meaning the numbers get bigger, getting greater pointing left is getting smaller so it gets less and less
Answer:
I'm pretty sure the answer is 40
Step-by-step explanation:
I added the 16 on both sides to the 48 and then divided it by 2. Hope this helps. I'm learning the same thing and the struggle is real but i like this site and we will get better. :)
Answer: f(3) = 23
Step-by-step explanation:
Put 3 where x is in the expression for f(x) and do the arithmetic.
... f(3) = 2·3^2 +5√(3-2)
... f(3) = 18 + 5 = 23