Answer:
The shearing stress is 10208.3333 Pa
The shearing strain is 0.25
The shear modulus is 40833.3332 Pa
Explanation:
Given:
Block of gelatin of 120 mm x 120 mm by 40 mm
F = force = 49 N
Displacement = 10 mm
Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain, SS = ?
The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:
A = 40*120 = 4800 mm² = 0.0048 m²
The shearing stress:
The shearing strain is defined as the tangent of the displacement that the block over its length:
Finally, the shear modulus is the division of the shearing stress over the shearing strain:
Answer:
The work done on the canister is 15.34 J.
Explanation:
Given;
mass of canister, m = 1.9 kg
magnitude of force acting on x-y plane, F = 3.9 N
initial velocity of canister in positive x direction, = 3.9 m/s
final velocity of the canister in positive y direction,
The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.
ΔK.E =
ΔK.E
The initial kinetic energy of the canister;
The final kinetic energy of the canister;
ΔK.E = 29.79 J - 14.45 J
ΔK.E = = 15.34 J
Therefore, the work done on the canister is 15.34 J.
Answer:
The final speed of the stone as it lift the ground is 23.86 m/s.
Explanation:
Given that,
Force acting on the rock, F = 3 N
Distance, d = 16 m
Initial speed of the stone, u = 22 m/s
We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :
So, the final speed of the stone as it lift the ground is 23.86 m/s.