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inna [77]
3 years ago
10

The uncertainty in the position of an electron along an x axis is given as 5 x 10-12 m. What is the least uncertainty in any sim

ultaneous measurement of the momentum component px of this electron?
Physics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

The least uncertainty in the momentum component px is 1 × 10⁻²³ kg.m.s⁻¹.

Explanation:

According to Heisenberg's uncertainty principle, the uncertainty in the position of an electron (σx) and the uncertainty in its linear momentum (σpx) are complementary variables and are related through the following expression.

σx . σpx ≥ h/4π

where,

h is the Planck´s constant

If σx = 5 × 10⁻¹²m,

5 × 10⁻¹²m . σpx ≥ 6.63 × 10⁻³⁴ kg.m².s⁻¹/4π

σpx ≥ 1 × 10⁻²³ kg.m.s⁻¹

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A car is designed to get its energy from a rotating
nydimaria [60]

Answer:

(a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power P= 15.0 hp = 15.0\times746=11190 watt

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}mr^2

Put the value into the formula

I=\dfrac{1}{2}\times475\times(1.50)^2

I=534.375\ kg m^2

(a). We need to calculate the kinetic energy stored in  the fly wheel

Using formula of K.E

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2

K.E=46880620.9\ J

K.E =46.88\times10^{6}\ J

K.E =46.88\ MJ

(b). We need to calculate the length of time the car could run before the flywheel  would have to be brought backup to speed

Using formula of time

t=\dfrac{46.88\times10^{6}}{11190}

t=4189.45\ sec

t=1.163\ hours

Hence, (a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

3 0
3 years ago
Question 20 (4 points)
irinina [24]

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

f _{net} = m(a)

So

250 = 50(a)

a = 5

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

3 0
2 years ago
Batteries can supply a steady flow of electrons.<br> True<br> False
Alecsey [184]

The answer is TRUE, batteries CAN supply a steady flow of electrons.

6 0
2 years ago
When a planet orbits the Sun, the
Anna [14]
I’m not sure I think it’s A
6 0
2 years ago
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A car travels up a hill at a constant speed of 38 km/h and returns down the hill at a constant speed of 66 km/h. Calculate the a
mojhsa [17]

Answer:

Average speed will be 48.23 km/h

Explanation:

Let the distance up to hill is = d km

Speed when car goes to hill = 38 km/h

So time required t=\frac{distance}{speed}=\frac{d}{38}hour

Speed when car return from hill = 66 km/h

So time required to return fro hill t=\frac{d}{66}h

Total time t_{total}=\frac{t}{38}+\frac{t}{66}

Total distance = d+d =2d

So average speed=\frac{total\ distance}{total\ time}=\frac{2d}{\frac{d}{38}+\frac{d}{66}}=48.23km/h

8 0
3 years ago
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