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3 years ago

HELP MY GRADES-

1 answer:

5 0

If you count the number of seconds between the flash of lightning and the sound of thunder, and then divide by 5, you'll get the distance in miles to the lightning: 5 seconds = 1 mile, 15 seconds = 3 miles, 0 seconds = very close. Keep in mind that you should be in a safe place while counting.

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A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How f

kiruha [24]

Work is obtained by multiplying the force and the object's displacement. The force and displacement and force should be in the same direction in order to have work.
W = F x d
d = W / F
Substituting the known values,
d = 352 J / 45 N = 7.82 m
Thus, the displacement of the student is 7.82 m.

8 0

4 years ago

States of matter depend in part on the___<br> of an item.

harina [27]

Answer:

Explanation:

Matter occurs in four states: solids, liquids, gases, and plasma.

States of matter are generally described on the basis of qualities that can be seen or felt.

A solid has a definite shape and volume because the molecules that make up the solid are packed closely together and move slowly.

7 0

3 years ago

NEED HELP ASAP!!!! DUE in 5 MINS!!!!<br><br>$20 in the ratio 1 to 4 WILL GIVE BRAINLIEST

rusak2 [61]

Answer:

$4 : $16

Explanation:

8 0

3 years ago

Read 2 more answers

Find the magnitude of pressure in Pascal of 150N that acts normally on area. Of 0.25m2

s2008m [1.1K]

Pressure = force/ area

= 150N/ 0.25m^2

= 600Pa

5 0

3 years ago

The sound intensity from a jack hammer breaking concrete is 2.0W/m2 at a distance of 2.0 m from the point of impact. This is suf

kupik [55]

Answer:

(a) $I_{1}=3.2*10^{-3}W/m^{2}$

(b) $\beta =95dB$

Explanation:

Given data

Distance r₁=50 m

Distance r₂=2 m

Intensity I₂=2.0 W/m²

To find

(a) The Sound Intensity I₁

(b) The Sound Intensity level β

Solution

For (a) the Sound Intensity I₁

$\frac{I_{1} }{I_{2}}=\frac{(r_{2})^{2} }{(r_{1})^{2} }\\I_{1} =I_{2}(\frac{(r_{2})^{2} }{(r_{1})^{2} })\\I_{1}=(2.0W/m^{2} )(\frac{(2m)^{2} }{(50m)^{2} })\\I_{1}=3.2*10^{-3}W/m^{2}$

For (b) the Sound Intensity level β

The Sound Intensity level β is calculated as follow

$\beta =(10dB)log_{10}(\frac{I}{I_{o} } )\\\beta =(10dB)log_{10}(\frac{3.2*10^{-3}W/m^{2} }{1.0*10^{-12} W/m^{2} } )\\\beta =95dB$

8 0

3 years ago