To solve this you have to add 98 and 82 together then divide by three so the answer would be 60
Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17
Answer:
Solution: (3, 2)
Step-by-step explanation:
It's easier to graph when the equation of the lines are in their slope-intercept form, y = mx + b.
<u>x - 3y = -3</u>
-3y = -x - 3
Divide both sides by -3:

y = 1/3x + 1
where slope = 1/3
y-intercept = 1
<u>x + y = 5</u>
Subtract x from both sides to isolate y:
x - x + y = - x + 5
y = -x + 5
where slope = -1
y-intercept, 5
I started by graphing the y-intercepts of each line. Then, I used the slope of each linear equation (rise over run) to plot the next points on the graph. In the attached screenshot of the graph, <u>x - 3y = -3</u> is the blue line, while <u>x + y = 5</u> is the green line. Their intersection occurs at point, (3, 2).
Therefore, the solution is (3, 2).
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Answer: Our required probability is 0.1695.
Step-by-step explanation:
Since we have given that
Number of male applicants = 4200
Number of female applicants = 3800
So, total number of applicants = 4200+3800 = 8000
Probability of male entered and subsequently enrolled is given by

Probability of female entered and subsequently enrolled is given by

Number of male entered and subsequently enrolled is given by

Number of female entered and subsequently enrolled is given by

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

Hence, our required probability is 0.1695.
Answer:
18) 6x^2-7x-5
19) 20x^2+17x-63
20) 18x^2-20x+2
21) 5x^2+42x+16
Step-by-step explanation:
Perimeter=length×breadth
18) (3x-5)(2x+1)
=6x^2+3x-10x-5
=6x^2-7x-5
19) (4x+9)(5x-7)
=20x^2-28x+45x-63
=20x^2+17x-63
20) (18x-2)(x-1)
=18x^2-18x-2x+2
=18x^2-20x+2
21) (5x+2)(x+8)
=5x^2+40x+2x+16
=5x^2+42x+16