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LiRa [457]
3 years ago
6

For problems 1 through 3, please include –

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

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How could the distance formula and slope be used to classify triangles and quadrilaterals in the coordinate plane?
S_A_V [24]

~ Use the distance formula to measure the lengths of the sides.

~ Use the slope to check whether sides are perpendicular and form right angles.

~ Use the slope to check whether the diagonals are perpendicular to each.

I hope this helps ^-^

7 0
3 years ago
Find the mass of 250 ml of water. The density of water is 1 g/ml.
alexandr1967 [171]

Answer:

250g

Step-by-step explanation :

250ml x 250g/ml = 250 g

To get the mass (in grams), you need to divide the ml's off and get the g alone.

7 0
3 years ago
Each dimension of a parallelogram is multiplied by a positive number n. Write an expression for the area of the new parallelogra
mixas84 [53]

Answer:

b*h

Step-by-step explanation:

therethere are four sides to a parallelogram and two of them would be h and b and you must multiply that by n then each other

New area:

(b*n) * (h*n) = (b*h)n^2

5 0
3 years ago
The sum of 3 times m and 4 times m
drek231 [11]

Answer:

7 meters

Step-by-step explanation:

(3*m) + (4*m)

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5 0
3 years ago
Read 2 more answers
Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7​
harina [27]

Given:

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

To verify:

a(b-c)=ab-ac for the given values.

Solution:

We have,

a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}

We need to verify a(b-c)=ab-ac.

Taking left hand side, we get

a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)

a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)

Taking LCM, we get

a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)

a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)

a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)

a(b-c)=-\dfrac{68}{35}\right)

Taking right hand side, we get

ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}

ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}

ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}

Taking LCM, we get

ab-ac=\dfrac{-28-40}{35}

ab-ac=\dfrac{-68}{35}

Now,

LHS=RHS

Hence proved.

7 0
2 years ago
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