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Studentka2010 [4]
2 years ago
12

What is the volume of a square pyramid with a 10 x 10 foot base and an altitude of 6 feet?​

Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0

Answer:

I believe the answer is 200 feet squared

Step-by-step explanation:

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7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
blondinia [14]

\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
1 year ago
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8593 g and a standard deviation of 0.
Alex17521 [72]

Answer:

The package label stated that the net weight is 381.8g If every package has ... brand of candies have a mean weight of 0.8616g and a standard deviation of ...

6 0
2 years ago
Which of the following is NOT a tax collected by the federal government? A. sales tax B. excise tax C. income tax D. payroll tax
Usimov [2.4K]
I believe the answer is B "excise tax" I think its this answer because I know that the goverment charges income tax, payroll tax, and sales tax.
4 0
3 years ago
Read 2 more answers
FREE BRAINLIEST, FIRST ANSWER = BRAINLIEST!
Law Incorporation [45]
Me just so I can ask a question
3 0
3 years ago
Read 2 more answers
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x<-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
3 years ago
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