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alexandr1967 [171]
3 years ago
7

Need help solving please!!!

Mathematics
1 answer:
Sidana [21]3 years ago
5 0

Answer:

Ha goood luck

Step-by-step explanation:

Ha goog

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Which equation can be used to find the surface area of the cylinder?
Verdich [7]

Answer:

S = π( 2(9) + 2(3)(14))

Step-by-step explanation:

Here we are to select which of the options best describe the equation that could be used to find the surface area of the cylinder.

Mathematically,

the surface area of a cylinder can be calculated using the formula

S = 2 π r^2 + 2 π rh

from the question, we have r as d/2 = 6/2 = 3cm and h = 14cm

We plug these two values into the equation above

Thus, we have

S = 2 * π * 3^2 + 2 * π * 3 * 14

S = π( 2(9) + 2(3)(14))

4 0
3 years ago
The volume of fuel in a tank changes at a rate given by the equation V'\left(t\right)=\frac{4t}{\sqrt[3]{t^2+3}},\:t\ge0 V ′ ( t
Ksju [112]
V'(t)=\dfrac{4t}{\sqrt[3]{t^2+3}}

The volume of fuel in the tank after 9 hours is given by

\displaystyle\int_0^9V'(t)\,\mathrm dt=\int_0^9\dfrac{4t}{(t^2+3)^{1/3}}\,\mathrm dt

To compute the integral, substitute u=t^2+3, so that \mathrm du=2t\,\mathrm dt. Then when t=0, u=0^2+3=3; when t=9, u=9^2+3=84.

\displaystyle\int_0^9V'(t)\,\mathrm dt=2\int_{t=0}^{t=9}\frac{2t}{(t^2+3)^{1/3}}\,\mathrm dt=2\int_{u=3}^{u=84}u^{-1/3}\,\mathrm du
=2\cdot\dfrac32u^{2/3}\bigg|_{u=3}^{u=84}=3(84^{2/3}-3^{2/3})\approx51.3

So the volume of fuel after 9 hours is about 51.3 gallons.
8 0
4 years ago
H = 210 + 33t
NeTakaya

Answer:

it depends on how long she lived there. if she loved there for say 18 years then your question would look like this

Step-by-step explanation:

h = 210 + 33 × 18

18 × 33 = 594

594 + 210 = 804

h = 804

6 0
3 years ago
Evaluate the expression when y = 2.
Yuki888 [10]

Answer:

Hiiiii

The answer is 4 + 2 + 7= 13

Sorry if it incorrect

Have a nice day

6 0
3 years ago
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X2+ x -12x-pWhat value should be substituted for p for the expression to reduce to (x + 4) ?
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Handball the Theo thaow d skskozoaow.
3 0
3 years ago
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