Answer:
2.5 pounds of Granny Smith apples.
Step-by-step explanation:
Answer:
-15 is the answer of this
Step-by-step explanation:
Rules in Algebra
Answer:
B.) 27ft
Step-by-step explanation:
The labeled points given: (5,18) and (1.5, 7.5)
Slope = (18 - 7.5)/(5-1.5) = 10.5 / 3.5 = 3
A linear model:
y - 18 = 3(x - 5)
y - 18 = 3x - 15
y = 3x + 3
If x = 8 seconds then the distance in feet (y) would be: (plug in x = 8 into the equation y = 3x + 3)
y = 3(8) + 3
y = 24 + 3
y = 27 ft
Answer:
B.) 27ft
Answer:
<h2>VX = 26</h2>
Step-by-step explanation:
If W is the midpoint of VX then VW = WX. Therefore we have the equation:
2x + 5 = 4x - 3 <em>subtract 5 from both sides</em>
2x = 4x - 8 <em>subtract 4x from both sides</em>
-2x = -8 <em>divide both sides by (-2)</em>
x = 4
VX = VW + WX
VX = 2x + 5 + 4x - 3 = (2x + 4x) + (5 - 3) = 6x + 2
Put the value of x = 4 to 6x + 2:
VX = 6(4) + 2 = 24 + 2 = 26
The total amount of calories burnt in jogging 2 miles = 185 calories
We have to determine the number of calories burned in jogging 3 miles.
Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.
So, the total amount of calories burnt in jogging 1 mile = 
= 92.5 calories
So, the amount of calories burnt in 3 miles = 
= 277.5 calories
Therefore, 277.5 calories are burned in jogging 3 miles.