Let
x---------> the larger number
y---------> the smaller number
we know that
x+y=148------> equation 1
x=3y-2------> equation 2
substitute 2 in 1
[3y-2]+y=148--------> 4y=150---------> y=150/4------> y=37.5
x=3y-2----> x=3*37.5-2-----> x=110.5
the answer is
the larger number is 110.5
the smaller number is 37.5
Answer:
Step-by-step explanation:
We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...
y = a(x -3)² +b
Filling in the values from the first two table points, we get
For (x, y) = (0, 6):
6 = a(0 -3)² + b ⇒ 9a +b = 6
For (x, y) = (2, 22):
22 = a(2-3)² +b ⇒ a +b = 22
Subtracting the second equation from the first gives ...
(9a +b) -(a +b) = (6) -(22)
8a = -16 . . . . . . collect terms
a = -2 . . . . . . . . divide by 8
The second equation above tells us ...
b = 22 -a = 22 -(-2) = 24
So, our equation for y is ...
y = -2(x -3)² +24
__
The value of y for x=5 is ...
y = -2(5 -3)² +24 = 16
The height of the ball after 5 seconds is 16 feet.
Answer:
4³
Step-by-step explanation:
16 x 4
(4 x 4) x 4 = 64
What is the minimum value of of the function below y = 2x2 – 8x + 11 O y=-3 O y = 2 O y = 3 O y = 11
The rate of giant tortoise is 1/10 meters per each second.
The rate of cooter turtle is 1/2 meters per each second.
How long would it take a giant <span>tortoise to travel 5 meters?
1 second : 1/10 m = X : 5 m
1/10x = 5
x = 50 seconds
How much longer would it take a giant tortoise than a cooter turtle to travel 10 meters on land?
1 second : 1/2 m = X : 10 m
1/2x = 10
x = 20 seconds
So the giant turtle can travel 5 meters in 50 seconds.
</span><span>So the cooter turtle can travel 10 meters in 20 seconds.</span>