Given=
length of the segment AD is 28 cm
distance between the midpoints of segments AB and CD is 16 cm
find out length of BC
To proof
AD = 28 cm
let the midpoint of the AB is E.
let the midpoint of the CD is F.
E & F are the midpoints i.e these points divide AB & CD in two equal parts.
Let BC = z
Let AE = EB = x ( E is midpoint)
Let CF = FD = y (F is midpoint)
the equation becomes
2x + 2y + z = 28
x + y + z = 16
mulitipy above equation by 2
we get
2x + 2y + 2z = 32
thus solving the equations
2x + 2y + 2z = 32
2x + 2y + z = 28
we get
z = 4 cm
i.e BC = 4 cm
Hence proved
Answer:
The x would equal 25
Step-by-step explanation: x equals 25 because you need to use Pythagorean Theorem to find the hypotenuse.
Oh please first if the rectangle was compete, it's area would be 8.
The area of the missing triangle is 
=2.
8-2=6<u> </u>
<u>And there you go! Your answer is 6.</u>
Answer:
∣∣−23∣∣ ∣∣29∣∣ ∣∣34∣∣ ∣∣−38∣∣ ∣∣−45∣∣ ∣∣−47∣∣ ∣∣−59∣∣ ∣∣67∣∣ ∣∣−78∣∣ ∣∣−110∣∣ ∣∣−514∣∣, ∣∣710∣∣
Step-by-step explanation:
Answer:
Step-by-step explanation:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]
