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3 years ago

The inpjt of the function

Mathematics

1 answer:

just olya [345]3 years ago

7 0

[Content Deleted] Sorry! Brainly.com has deleted this person's answer!

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How to do 30(c) ??????

adelina 88 [10]

Answer:

A kite with a 100 foot-long string is caught in a tree. When the full length of the string is stretched in a straight line to the ground, it touches the ground a distance of 30 feet from the bottom of the tree. Find the measure of the angle between the kite string and the ground.

17°

27°

63°

73°

Step-by-step explanation:

3 0

3 years ago

Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav

KiRa [710]

Answer:

He must earn $2,400 to cover both leisure and $2,160 for school expenses.

Step-by-step explanation:

Let the total amount Ken must earn be k. Then 10% of that would cover leisure activities and the remaining 90% specifically for school expenses.

Then 0.90k = $2,160, and k = $2,400.

He must earn $2,400 to cover both leisure and $2,160 for school expenses.

7 0

3 years ago

2(y-3)-y=-1 please help me with this one

emmasim [6.3K]

Y=<span>5 is your answer. Hope this helps :)</span>

5 0

3 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

2 years ago

Use this equation to find dy/dx. 3y cos x = x2 + y2

Art [367]

Given: 3y cos x = x² + y²

Define $y' = \frac{dy}{dx}$

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)

Answer:
$\frac{dy}{dx} = \frac{2x+3y \, sin(x)}{3cos(x)-2y}$

5 0

3 years ago