Answer:
Original number = 38
Step-by-step explanation:
10*x + y
x = y - 5
10y + x = 2 (10x + y) + 7
10y + y - 5 = 2(10(y - 5) + y) + 7
11y - 5 = 2(10y - 50 + y ) + 7
11y - 5 = 2(11y - 50) + 7
11y - 5 = 22y - 100 + 7
11y - 5 = 22y - 93
11y + 88 = 22y
88 = 11y
y = 8
x = y - 5
x = 8 - 5
x = 3
So the original number is 38. Does that work?
3 is 5 less than 8.
83 = 2*38 + 7
83 = 76 + 7
83 = 83. Yes it works.
1150, i’m pretty sure that’s it!
The graph is vertically stretched by a factor of 2 and translated 3 units right when it is transformed. Option A is correct.
<h3>What is transformation of a function?</h3>
Transformation of a function is shifting the function from its original place in the graph.
Types of transformation-
- Horizontal shift- Let the parent function is f(x). Thus by replacing parent function with f(x-b) shifts the graph b units right and by replacing parent function with f(x+b) shifts the graph b units left.
- Vertical shift- Let the parent function is f(x). Thus by replacing parent function with f(x)-c shifts the graph c units down and by replacing parent function with f(x)+c shifts the graph c units up.
The given function is,

This function is changed to the function,

Here the 3 units is substrate in the function. Thus, it is shiftet 3 units right. The number 2 is multiplied in the function which vertically stretched the graph by a factor of 2.
Thus, the graph is vertically stretched by a factor of 2 and translated 3 units right when it is transformed. Option A is correct.
Learn more about the transformation of a function here;
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4000.0093979 = 63.2456275
-15999998
= 8.7
Then you get 50
Answer:
For a sample size of 10, the t-value is about 3.25 (from tables) at a 99% confidence interval.
Explanation:
When the standard deviation for the population is not known, the confidence interval estimate for the population mean is performed with the Student's t-distribution.
The confidence interval for the mean is calculated as

where

= sample mean,
s = sample standard deviation,
t = t-value (provided in tables),
n = sample size.
When reading the t-value, (n-1) is called the df or degrees of freedom.