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morpeh [17]
3 years ago
7

Translate the phrase into an algebraic expression The sum of 7 and c​

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

7 + c

Hope this helps

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And the
matrenka [14]

Answer:

A) The legs are 9 & 12 inches.

B) The hypotenuse is 15 inches.

<em>Hope that helps! :) <3</em>

Step-by-step explanation:

8 0
3 years ago
Which relation is not a function
3241004551 [841]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Kolby decided he wanted to go to the amusement park. The amusement park charges $8.00 for entry and $1.40 for each ride.
Dmitry_Shevchenko [17]

Answer:

Part A:

1.40x+8.00=C

Part B:

1.40x+8=26

        -8   -8

1.40x=18

/1.40    /1.40

x=11 total rides

Step-by-step explanation:

An expression to represent this would be 1.40x+8.00=C (C is total cost).

If you had $26.00 you would first spend $8.00 on the entry leaving you with $18.00. Then you would divide the $18 by $1.40 for each ride to get 12.8... It doesn't make sense to go on a fraction of a ride so you just round down to 11 rides

8 0
3 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
2 years ago
The hanger image below represents a balanced equation.
Savatey [412]

Answer:

The answer is 1/5 + z = 3/5

Step-by-step explanation:

6 0
3 years ago
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