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joja [24]
4 years ago
14

81 1/4 is equal to 2. True or False

Mathematics
1 answer:
Rus_ich [418]4 years ago
7 0
False.
81 1/4 is much greater than 2.
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You buy a car for $8000 that depreciates at a rate of 11% a year. How much is the
Fiesta28 [93]

Answer: $4,467.2

Step-by-step explanation:

The formula for this is A = P (1 - r) ^t

Where p is the Principal, r is the rate and t= time

Given from the question, p = $8000

rate= 11% = 11/100 = 0.11

Time = 5 years

Slot the values into the formula:

A= 8000 (1 - 0.11) ^5

= 8000 (0.89)^5

8000 × 0.5584

=$4,467.2

After 5 years, the worth of the car would have depreciated to $4,467.2

I hope this helps.

8 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=37x%3D9x%2B4" id="TexFormula1" title="37x=9x+4" alt="37x=9x+4" align="absmiddle" class="latex-
Gre4nikov [31]
4
37x=9x+4
STEPS TO SOLVE
1
Subtract
9
x
9x from both sides of the equation

37
x
=
9
x
+
4
37x=9x+4
37
x
−
9
x
=
9
x
+
4
−
9
x
37x−9x=9x+4−9x
2
Simplify

Combine like terms
37
x
−
9
x
=
9
x
+
4
−
9
x
37x−9x=9x+4−9x
28
x
=
9
x
+
4
−
9
x
28x=9x+4−9x
Combine like terms
28
x
=
4
28x=4
3
Divide both sides of the equation by the same factor

28
x
=
4
28x=4
28
x
28
=
4
28
28
28x
​
=
28
4
​

4
Simplify

Simplify fraction
28
x
28
=
4
28
28
28x
​
=
28
4
​

x
=
4
28
x=
28
4
​

Divide the numbers
x
=
1
7
x=
7
1
​

SOLUTION
8 0
3 years ago
PLEASE HELP WILL GIVE BRAINIEST
Phantasy [73]

The answer would be D. hope this helps :))

8 0
3 years ago
Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne
Marizza181 [45]

Answer

test statistic t =  -2.27    

P-value p- value  =  0.0198

Step-by-step explanation:

From the question we are told that

     The  first  sample  size is  n_1  = 5

     The first  sample mean is  \= x_1  =  1.76 \ mm

     The first  standard is  s_1   =  0.55

     The second is sample \ size\ is\  n_2 =  11

     The second sample mean is  \= x_2   = 2.56

     The second standard deviation is  \sigma =  0.84

      The level of significance is \alpha  =  0.01

The  null hypothesis is H_o :  \mu_1 - \mu_2 = 0

The  alternative hypothesis is  H_a: \mu_1 - \mu_2 <  0

Generally the test statistics is mathematically represented as

           t =  \frac{ (\= x _1 - \= x_2) - ( \mu_1 - \mu_2)}{ \sqrt{\frac{s_1 ^2 }{ n_1 }  + \frac{s_1 ^2 }{ n_1 }  } }

=>        t =  \frac{ (1.76 - 2.56 ) - 0 }{ \sqrt{\frac{0.55^2 }{ 5 }  + \frac{0.84^2 }{11 }  } }

=>        t =  -2.27      

Generally degree of freedom is mathematically represented as

          df  = n_1 + n_2 - 2

=>       df  = 5 + 11 - 2

=>       df  = 14

From the student t distribution table the probability value to the left that corresponds to t =  -2.27  at a degree of freedom of  df  = 14 is  

        p- value  =  0.0198

           

         

6 0
3 years ago
3/2y - 3 + 5/3 z when y= 6 and z = 3.
wel

Hope this helps some lol

4 0
4 years ago
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