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agasfer [191]
3 years ago
7

3. The measure of one angle is ten less than four times the measure of the other angle. The sum of the measures of the two angle

s is 90°. Determine the measure of each of the angles.
Mathematics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

go to Mr.beast.com

Step-by-step explanation:

he can give you a lot of money and free stuf

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Answer the question in the picture​
7nadin3 [17]

Answer:

10²

Step-by-step explanation:

left triangle = 2 × 2 = 4 ÷ 2 = 2²

right triangle = 2 × 4 = 8     8 ÷ 2 = 4²

middle square = 2 × 2 = 4²

2 + 4 + 4 = 10²

7 0
3 years ago
Y=(x-1)^2+2 find the y-intercept
dybincka [34]

Answer:

(0,3)

Step-by-step explanation:

So we have the equation:

y=(x-1)^2+2

Recall what the y-intercept is. The y-intercept is when the graph crosses the y-axis. Therefore, at that point, the x-value is 0. So, to find the y-intercept, substitute 0 for x. Thus:

y=(0-1)^2+2

Subtract:

y=(-1)^2+2

Square:

y=1+2

Add:

y=3

So, the y-intercept is at (0,3).

And we're done!

3 0
3 years ago
A(n) (blank) is a triangle with at least two congruent sides<br> (fill in the blank please)
OlgaM077 [116]

Answer:

isosoles or equilateral

Step-by-step explanation:

Since it says at least it can equlateral but an equaltral triangle can also be called isosoles

6 0
3 years ago
Am i doing this right?
Vaselesa [24]
Yes you are doing it right

3 0
3 years ago
Read 2 more answers
F(x) = -4x(2)+ 12x – 9
kenny6666 [7]

For this case we have the following function:

f (x) = - 4x ^ 2 + 12x-9

y = 0 we have:

-4x ^ 2 + 12x-9 = 0

Where:

a = -4\\b = 12\\c = -9

By definition, the discriminant of a quadratic equation is given by:

d = b ^ 2-4 (a) (c)

d> 0: Two different real roots

d = 0: Two equal real roots

d: Two different complex roots

Substituting the values we have:

d = (12) ^ 2-4 (-4) (- 9)\\d = 144-144

d = 0

We have two equal real roots.

To find the intersections with the x axis, we do y = 0:

-4x ^ 2 + 12x-9 = 0

We apply the quadratic formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values we have:

x = \frac {-12 \pm \sqrt {12 ^ 2-4 (-4) (- 9)}} {2 (-4)}\\x = \frac {-12 \pm \sqrt {144-144}} {- 8}\\x = \frac {-12 \pm0} {- 8}\\x = \frac {-12} {- 8}\\x = \frac {3} {2}

The intersection with the x axis is(\frac {3} {2}, 0)

Answer:

d = 0

The intersection with the x axis is (\frac {3} {2}, 0)

5 0
3 years ago
Read 2 more answers
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