Answer:
b) True. the force of air drag on him is equal to his weight.
Explanation:
Let us propose the solution of the problem in order to analyze the given statements.
The problem must be solved with Newton's second law.
When he jumps off the plane
fr - w = ma
Where the friction force has some form of type.
fr = G v + H v²
Let's replace
(G v + H v²) - mg = m dv / dt
We can see that the friction force increases as the speed increases
At the equilibrium point
fr - w = 0
fr = mg
(G v + H v2) = mg
For low speeds the quadratic depended is not important, so we can reduce the equation to
G v = mg
v = mg / G
This is the terminal speed.
Now let's analyze the claims
a) False is g between the friction force constant
b) True.
c) False. It is equal to the weight
d) False. In the terminal speed the acceleration is zero
e) False. The friction force is equal to the weight
It obeys law because the physics of quantum space are so slow and small it’s actually really fast
The speed of sound follows the same rules, just like any other speed, if the acceleration is zero.
distance = speed * time
distance = 2m
speed = 333m/s
Solve for time t.
Hand grip test an example of an isometric muscle contraction.
Isometric(increased pressure but no shortening)
Explanation:
- Isometric contraction, is one in which the muscle is activated, but instead of being allowed to lengthen or shorten, it is held at a constant length.
- An isometric exercise is a form of exercise involving the static contraction of a muscle without any visible movement in the angle of the joint.
- Isometric exercises are contractions of a particular muscle or group of muscles. During isometric exercises, the muscle doesn't noticeably change length and the affected joint doesn't move. Isometric exercises help maintain strength. They can also build strength, but not effectively.
- Isometric exercise is also known as static strength training. (Examples include the plank and side bridge as well as the wall sit and many yoga poses such as chair and tree poses).