The movements of the tectonic plates
<span>Cobalt-60 is undergoing a radioactivity decay.
The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span> n </span>⇒ remaining mass of cobalt after 3 years
T ⇒ decaying period
t ⇒ half-life of cobalt.
So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
3/t= 0.567
t = 3÷0.567
= 5.290626524
the half-life of Cobalt-60 is 5.29 years.
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Answer:
20m/s due east
Explanation:
Given parameters:
Displacement eastward = 200m
Time = 10s
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by time;
Velocity = 
Velocity = 
= 20m/s due east
Explanation:
C.
Object A will require more force to be set in motion but will travel faster than object B.
2. true
