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Paha777 [63]
3 years ago
9

what would be more damaging:having a head-on collision with an identical car at the same speed or driving head on into a crash b

arrier? explain
Physics
1 answer:
natali 33 [55]3 years ago
4 0
A head on collision would be worse and it would actually be four times as worse since the speed is doubled and energy is a squared value so by far a head on collision with another car
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Rewrite Newton's first law of motion in your own words.
BlackZzzverrR [31]
Newton's first law is called inertia, or the force an object has to resist unbalanced forces that are placed upon it. The more mass an object has, the more inertia an object has. The less mass an object has, the less inertia an object has.
4 0
3 years ago
An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. It flies up to its nest in a tree at a height of 25 m. How much
erma4kov [3.2K]

Answer: 882 J

Explanation:

Correct on E2020

4 0
3 years ago
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An object floats in water with 5 8 of its volume submerged. The ratio of the density of the object to that of water is
ki77a [65]

Answer:

\dfrac{5}{8}

Explanation:

m = Mass of object = \rho v

m' = Mass of water = \rho' v'

\rho = Density of object

\rho' = Density of water

Weight of the water displaced is the force in the case of floating objects

According to the question

v'=\dfrac{5}{8}v

In the case of floating objects

W=W'\\\Rightarrow mg=m'g\\\Rightarrow \rho vg=\rho'v'g\\\Rightarrow \rho v=\rho' \dfrac{5}{8}vg\\\Rightarrow \rho=\rho' \dfrac{5}{8}\\\Rightarrow \dfrac{\rho}{\rho'}=\dfrac{5}{8}

The ratio of the density of the object to that of water is \dfrac{5}{8}

3 0
3 years ago
To compare the hearing capacities of 5 of his friends, Ravi designs a simple experiment. He places a CD player at the end of a l
aliya0001 [1]

Answer:

A) having each person listen to just 1 song instead of 5.

Explanation:

Ravi could accurately use the outcome to compare the hearing capacities of his friends by this experiment if appropriate precautions are observed.

Playing 5 well known songs simultaneously could result to the interference of sounds when each participant moves away from the player. Which could naturally cause the variation in volume of the songs played with respect to the increasing distance.

Therefore, the reliability of the result from this experiment can be increased if each person listen to just 1 song instead of 5 at a predetermined volume. Each participant would be able to focus on hearing a song during the experiment.

8 0
4 years ago
A parallel plate capacitor is made of two large plates ofarea
Murrr4er [49]

Answer:

C = \frac{\epsilon_0 \epsilon_1 A}{\epsilon_0 t + \epsilon_1(a-t)}\\

Explanation:

If there is a dielectric slab with thickness less than the distance between the plates is inserted inside a capacitor, then that capacitor can be regarded as two capacitors connected in series.

Let's assume that the slab is placed onto the lower side. So, the capacitance of that part of the capacitor, C1 is

C_1 = \epsilon_1\frac{A}{t}

where \epsilon_1 is the permittivity of the slab.

The other part of the capacitor is

C_2 = \epsilon_0 \frac{A}{a-t}

Two capacitors are connected in series:

\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{\epsilon_1 \frac{A}{t}} + \frac{1}{\epsilon_0 \frac{A}{a-t}} = \frac{t}{\epsilon_1 A} + \frac{a-t}{\epsilon_0 A} = \frac{\epsilon_0 t + \epsilon_1 (a-t)}{\epsilon_0 \epsilon_1 A}\\C = \frac{\epsilon_0 \epsilon_1 A}{\epsilon_0 t + \epsilon_1(a-t)}

If we know the charge of the plates, we could relate the potential V0 to capacitance via

C = \frac{Q}{V_0}

4 0
3 years ago
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