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Paha777 [63]
3 years ago
9

what would be more damaging:having a head-on collision with an identical car at the same speed or driving head on into a crash b

arrier? explain
Physics
1 answer:
natali 33 [55]3 years ago
4 0
A head on collision would be worse and it would actually be four times as worse since the speed is doubled and energy is a squared value so by far a head on collision with another car
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1. What is the kinetic Energy of a 1500kg object moving at 21 m/s?
Wewaii [24]
The formula for working out kinetic energy is

=122

KE = kinetic energy
m = mass of a body
v = velocity of a body


kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

For the first one I think :
Answer:
KE = 330750 J

I’m not sure about the second one- sorry

The third is
Answer:
KE = 41454 J

Hope it helps and it is correct, sorry if it isn’t !
8 0
3 years ago
How does 1 horsepower compare to 1 watt power​
yaroslaw [1]

"Life is wasted if we do not grasp the glory of the cross, cherish it for the treasure that it is, and cleave to it as the highest price of every pleasure and the deepest comfort in every pain. What was once foolishness to us—a crucified God—must become our wisdom and our power and our only boast in this world.” - John Piper

8 0
3 years ago
Read 2 more answers
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
4 years ago
You walked a dog 0.75 miles. how many kilometers did you walk? (1 mile equals about 1.61 km)
Digiron [165]
What we have so far:
*Distance you walked the dog = 0.75 miles
*Conversion: 1 mile is approximately 1.61 kilometers

What we are trying to find:
*Distance you walked the dog in kilometers.

To solve this problem we must:
*We must employ conversion first.
Step 1) 0.75miles x 1.61km/1miles <--- Multiplication will be employed.

Step 2) 0.75 x 1.61/1 (km)<--- notice that we deleted the unit "miles". We did that to make sure that the result will be in kilometers (km).

Step 3) 0.75 x 1.61(km) <--- Since we are already done with the conversion process, we now have to multiply the distance and the conversion factor.

Step 4) 1.2075km <--- Raw result.

Step 5) Rounding it up to two decimal places: 1.21km

Therefore, the correct answer is: D. 1.21km
7 0
4 years ago
Calculate the power of a car that uses 12KJ of chemical energy in 6 seconds
PolarNik [594]

Explanation:

Power=work done/time

=> 12kJ/6s = 12000J/6s = 2000W = 2kW.

hope this helps you

8 0
3 years ago
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