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a_sh-v [17]
3 years ago
12

4 3/4 X 4 1/7 what is it please help

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
7 0

first you turn the fractions into inproper fractions by multiplying the whole number by the denomonator and adding the numerator

4×4=16

16+3=19

19/4

4×7=28

28+1=29

29/7

keep the denomonators the same. now that you've converted them into inproper fractions you can multiply them

19/4 × 29/7=551/28

there is no way to simplify this answer so this is the final answer

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A recipe calls for 2 1/2 cups of sugar. You have 2 2/3 cups of sugar. Do you have enough sugar? If not, how much more sugar is n
Karo-lina-s [1.5K]

The difference between the cups of sugar is 1/6, hence you have enough sugar.

<h3>Difference and sum of fractions</h3>

Fractions are written as a ratio of two integers, For instance, a/b is a fraction where a and b are integers.

According to the question, a recipe calls for 2 1/2 cups of sugar. If have 2 2/3 cups of sugar;

Difference of cups of sugar = 2 2/3 - 2 1/2

Convert to improper fraction

Difference = 8/3 -  5/2

Difference = 16-15/6

Difference = 1/6

Since the difference between the cups of sugar is 1/6, hence you have enough sugar.

Learn more on fraction here: brainly.com/question/17220365

#SPJ1

3 0
2 years ago
B(h+w)=4h(11-j), solve for w
frozen [14]

Answer:

W=4h(11-j)/b-h

Step-by-step explanation:

Eliminate variables on the left side first.

b(h+w) = 4h (11-j) - so, divide b by both sides

(h+w)/b=4h(11-j)/b  then, eliminate h by subtracting on both sides.

(h+w)-h=4h(11-j)/b - h   (h is eliminated on the left side and now you are left with

W=4h(11-j)/b - h

   

4 0
3 years ago
In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons
GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

In\:\triangle AOC \:\&\:\triangle BOD

AO \cong OB.... (given)

\angle AOC \cong\angle BOD

(vertical \: \angle s)

CO \cong OD.... (given)

\therefore \triangle AOC \:\cong\:\triangle BOD

(SAS \: postulate)

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

AC = BD

m\angle OAC = m\angle OBD

m\angle OCA = m\angle ODB

7 0
3 years ago
the ticket booth at a school play sells 140 adult tickets and 210 student tickets. find the ratio of adults to students write yo
julsineya [31]

ratio of adults to students can be written as a fraction


adult tickets / student tickets

140/210 can be simplified to 14/21

14/21 can be simplifed to 2/3

6 0
3 years ago
Read 2 more answers
Tony has a hosepipe. The length of the hosepipe is 20 m. Tony stores the hosepipe on a reel. The weight of the reel is 1.4 kg. 1
harina [27]

Answer:

the total weight of the hosepipe and the reel is 7.4 kg

Step-by-step explanation:

First, we need to find the weight of the hosepipe, we know that 1/2 metre of the hosepipe has a weight of 150 grams, therefore we can conclude that 1 meter has a weight of (150)(2) = 300 grams.

If one meter weighs 300 grams, then 20 meters have a weight of 20(300) = 6000 grams. But since 1000 grams are 1 kg, this would be equivalent to 6 kg.

Now, to find the total weight of the hosepipe and the reel we are going to sum up the 2 weights:

Total weight = hose pipe weight + reel weight

Total weight = 6 kg + 1.4 kg

Total weight = 7.4 kg.

Therefore, the total weight of the hosepipe and the reel is 7.4 kg

8 0
3 years ago
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