The difference between the cups of sugar is 1/6, hence you have enough sugar.
<h3>Difference and sum of fractions</h3>
Fractions are written as a ratio of two integers, For instance, a/b is a fraction where a and b are integers.
According to the question, a recipe calls for 2 1/2 cups of sugar. If have 2 2/3 cups of sugar;
Difference of cups of sugar = 2 2/3 - 2 1/2
Convert to improper fraction
Difference = 8/3 - 5/2
Difference = 16-15/6
Difference = 1/6
Since the difference between the cups of sugar is 1/6, hence you have enough sugar.
Learn more on fraction here: brainly.com/question/17220365
#SPJ1
Answer:
W=4h(11-j)/b-h
Step-by-step explanation:
Eliminate variables on the left side first.
b(h+w) = 4h (11-j) - so, divide b by both sides
(h+w)/b=4h(11-j)/b then, eliminate h by subtracting on both sides.
(h+w)-h=4h(11-j)/b - h (h is eliminated on the left side and now you are left with
W=4h(11-j)/b - h
Answer:
SEE EXPLANATION
Step-by-step explanation:
So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:
ratio of adults to students can be written as a fraction
adult tickets / student tickets
140/210 can be simplified to 14/21
14/21 can be simplifed to 2/3
Answer:
the total weight of the hosepipe and the reel is 7.4 kg
Step-by-step explanation:
First, we need to find the weight of the hosepipe, we know that 1/2 metre of the hosepipe has a weight of 150 grams, therefore we can conclude that 1 meter has a weight of (150)(2) = 300 grams.
If one meter weighs 300 grams, then 20 meters have a weight of 
grams. But since 1000 grams are 1 kg, this would be equivalent to 6 kg.
Now, to find the total weight of the hosepipe and the reel we are going to sum up the 2 weights:
Total weight = hose pipe weight + reel weight
Total weight = 6 kg + 1.4 kg
Total weight = 7.4 kg.
Therefore, the total weight of the hosepipe and the reel is 7.4 kg
