Answer: The percentage of hotels in the city have a nightly cost of more than $200 is 21%
Step-by-step explanation:
Since the nightly cost of hotels in a certain city is normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the nightly cost of hotels.
µ = mean cost
σ = standard deviation
From the information given,
µ = $180.45
σ = $24.02
The probability that a hotel in the city has a nightly cost of more than $200 is expressed as
P(x > 200) = 1 - P(x ≤ 200)
For x = 200,
z = (200 - 180.45)/24.02 = 0.81
Looking at the normal distribution table, the probability corresponding to the z score is 0.79
Therefore,
P(x > 200) = 1 - 0.79 = 0.21
The percentage of hotels in the city have a nightly cost of more than $200 is
0.21 × 100 = 21%
Answer:
Step-by-step explanation:
4, 6, 7, 9, 10, 4, 6, 5, 4
First we will order them least to greatest.
4,4,4,5,6,6,7,9,10
Now we will add them all up.
We get 55.
Now we will divide 55 by the amount of numbers there are (9).
55/9= 6.11111
SO 4.9 and 6 are both less than the mean of the data set.
Answer:
M5|L12 Fractional Sides
Step-by-step explanation: answer is in the link. copy and paste it. Trust me!
Radius is the half of diameter.
That means the radius is 2inch/2=1inch.
Good luck mate!
