Answer:
option 4
Step-by-step explanation:
fog(x)=(x-5)²+4
=x²-10x+25+4
fog(x)=x²-10x+29
Volume=legnthn times width times height
a cubes legnth=width=height
therefor
volume=legnth^3
volume is greather than 125
125<legnth^3
cube root both sides
5<legnth
th elegnth is anything greather than 5
an example of some numbers are
6,7,30,3240958049238043284023848239048023843,
<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation



∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
Answer:
if the question is 2xy²(23x²y³) then the answer is 46x³y^5
Step-by-step explanation:
Answer:
The greatest number of 15 inches pieces that can be cut from 5 rolls of length 9 feet is: 35
Step-by-step explanation:
Given
Total length of one roll of ribbon = 9 feet
As the pieces have to be cut into inches, we will convert the measurement in feet to inches
As there are 12 inches in one feet, 9 feet will be equal to:
9*12 = 108 inches
Now first of all, we have to see how many 15 inches pieces can be cut from one role
So,

So the seamstress can cut 7 15-inch long pieces from a roll.
Now given that he has to cut from 5 rolls, the total number of 15-inch pieces will be:

Hence,
The greatest number of 15 inches pieces that can be cut from 5 rolls of length 9 feet is: 35